Numerical 02

Six lead-acid type of secondary cells, each of emf 20 V and internal resistance 0.015W, are joined in series to provide a supply to a resistance of 8.5W. Determine (i) the current drawn from the supply and (ii) it's voltage.

Sub Topics

Suggested solution:

Suggested solution:

emf of series combination of cells = 6 x 2 V = 12 V

Total internal resistance of series combination = 6 x 0.015 W = 0.09 W

Total resistance of circuit = (8.5 + 0.09) ohm = 8.59 ohm

Terminal potential difference