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Effects of Currents Problems - Numerical 05

In a silver-plating system, an electrolysis current of 5.0 A is used for a certain time and 0.5 moles of silver is deposited. How many moles of copper and iron will be deposited in their respective plating system if an electrolysis current of 10.0 A is passed for twice the time for silver plating?

Relative atomic mass of silver = 107.3

copper = 63.54

iron = 55.85

Sub Topics
  • Suggested solution:
  • Alternative Method
 

Suggested solution:

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The valency of silver is one. So, silver is monoatomic. Thus, the chemical equivalent of silver is the same as the molar mass of silver.

Since charge required to liberate one chemical equivalent of silver is 96500 C, therefore, the charge q required to liberate 0.5 chemical equivalent of silver is 0.5 x 96500 C, i.e., 48250 C.

Let us now calculate the moles of copper deposited.

I= 10A; t=2 x 9650s. Atomic mass of copper = 63.54

Since the valency of copper is 2,

Clearly, one mole of copper is liberated and hence deposited.

Now to calculate the moles of iron deposited,

Alternative Method

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Double the current for double the time will deposit 0.5 x 2 x 2 mole i.e., 2 mole of silver.


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