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Comparison of Linear and Rotational Motion

When a rigid body such as a merry-go-round rotates around an axis, each particle in the body moves in its own circle around that axis. Since the body is rigid, all particles make one revolution in the same amount of time. i.e., they all have the same angular speed w.

circle travelled

However, far a particle is from the axis, greater the circumference of its circular trajectory, the greater its linear speed. Let us try to relate the linear variables 'S', 'v' and 'a' for a particular point in a rotating body to the angular variables q, w of the body. The two sets of variables are related by r, the perpendicular distance of the point from the rotation axis. It is also the radius 'r' of the circle traveled by the point around the axis of rotation.

Sub Topics
  • The position
  • The speed
  • The acceleration
  • Combining all the above equations, a table can be framed that compares the translation and rotational motion parameters.
 

The position

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If a reference line on a rigid body rotates through an angle , a point within the body at a position 'r' from the rotation axis moves a distance 's' along a circular arc where 's' is given by


 

The speed

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Differentiating equation (1)

The acceleration

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Differentiating equation (2)

We get represents only the part of the linear acceleration that is responsible for changes in the magnitude 'v' of the linear velocity . Let us call it tangential component at.

Combining all the above equations, a table can be framed that compares the translation and rotational motion parameters.

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 Pure translation (fixed direction)  Pure rotation (fixed axis)
 Position x  Angular position θ
  Velocity v = dx/dt   Angular velocity ω= dθ/dt
  Acceleration a = dv/dt   Angular acceleration α= dω/dt
 Mass m  Rotational inertia I
 Newton’s second law Fnet = ma  Newton’s second law tnet = I α
 Work w=∫ Fdx  Work w= ∫ tdθ
 Kinetic energy K = ½ mv2  Kinetic energy K = ½ I ω2
 Power (constant force) P = Fv  Power (constant torque) P = t ω
 Work — kinetic energy theorem W = Δk  Work — kinetic energy theorem W = Δk
 Equations of translational motion v=u+at
S=ut+½ at 2
v2=u2+2as
 Equation of rotational motion ω = ω 0+ αt
θ= ω0 t + ½ α t2
ω2= ω02 + 2 αθ


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