Applications of velocity-time graphs
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The following results can be deduced from velocity-time graph.
- The acceleration produced in a body
- The distance covered by a moving object
- We can derive the equations of motion
Let us see how to calculate the distance covered by a moving object from speed-time graph.
The figure below gives the speed-time graph of a car moving with a uniform speed of 60kmp/hr for 5 hours.

Speed-Time graph of a car moving with a uniform speed
Distance traveled by the car (s) = v x t


But 60 km/h = BC = breadth of the rectangle OABC
5hr = OC = length of the rectangle OABC
i.e., the distance covered by the car = length x breadth = 300 km.
i.e., in order to calculate the distance covered by a moving object from a speed-time graph we just have to find the area enclosed by the speed-time graph and the time axis.
In case of non-uniform motion, the distance covered by the object cannot be found as the product of speed and time interval given by the speed-time graph because the speed does not remain constant throughout its motion. But, it is given by the area enclosed by the speed-time graph and the time axis.
The figure given below gives the motion of an object moving with variable speed.

Motion of an object moving with variable speed
The speed of the object is increasing in steps. The speed remains constant during the time interval 0 - t1, t1 - t2, t2 - t3 ......

The total distance covered by the object during the time interval
0 ----> t6 = Area of rectangle 1 + area of rectangle 2 +……+ area of rectangle 6.