A typical oblique collision in two dimensions
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A body of mass m1 is moving with a velocity 
along X-axis. Let it suffer elastic collision with a stationary body of mass m2. The distance b, between the initial line of motion and a line parallel to it through the centre of the target body is called the impact parameter. This is a measure of the directness of the collision. It may be defined as the distance by which the collision misses being head-on.
Clearly, for a head-on collision, b = 0.
After collision, let body of mass m1 be deflected at angle q1 with the initial direction. The body of mass m2 is deflected at angle q2 with the initial direction.
Let 
be the velocities of bodies of masses m1 and m2 respectively, after the collision.
Applying the law of conservation of momentum to the X-component of motion, we get
For Y - component of motion,
The collision is elastic. So kinetic energy will be conserved.
In the equations (1), (2) and (3) v
1f and v
2f can be resolved
, if m
1, m
2, v
1f, v
2f,
q1 and
q2 are known.
Coefficient of restitution
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According to Newton's experimental law of impact, the ratio of relative speed of separation after collision and the relative speed of approach before collision is constant. This constant is called coefficient of restitution or coefficient of resilience. It is denoted by e. It is a measure of the degree of elasticity of a collision. Its value depends upon the nature of the colliding bodies.
For a perfectly elastic collision, the value of e is 1. If 0 < e < 1, then the collision is inelastic. For a perfectly inelastic collision, e = 0. If e > 1, then the collision is a super-elastic collision. (An example of super elastic collision is that of a cracker which is forcefully struck against the ground.)
