Moving Charges and Magnetism Problems - Numerical 09

A long, thin straight solenoid has 500 turns wound over a length of 50cm. It carries a current of 0.5A. What is the magnetic field inside this solenoid?

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Suggested solution:

Suggested solution:

The magnetic field B, at a point on the axis is

B = m_onI / L

Given: N = 500 : L = 50 cm = 0.5m : I = 0.5A

B = 4 x 10^-⁷ x 5 x 10² x 0.5 / 5 x 10^-¹ = 6.284 x 10^-⁴ T