Optics Problems - Numerical 20

In Young's double slit experiment, the intensity at a point is 75% of maximum intensity. What is the smallest distance of this point from the central fringe? Given d = 0.1mm, D = 1m and l = 600 nm.

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Suggested solution:

Suggested solution:

The intensity I at a point on the screen where the two disturbances arrive having a phase difference s is

I = 0.751_m_a_x Therefore,

Let x be the minimum distance of this point from the central fringe.

Then,